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Volumes of Prisms & Pyramids - Lesson 12-4
Today we began to discuss volume, which we defined as follows:
![Definition of Volume](VolumeDefinition.gif)
We looked at the following example, the solution to which we determined to be 24 (2 X 4 X 3):
![Example 1](VolumeExample1.gif)
And the following, the solution to which we determined to be 192 (4 X 8 X 6):
![Example 2](VolumeExample2.gif)
Then, we thought about how we would find the volume of the cylinder shown below. We determined that we'd find the area of the base (a circle) and multiply it by the height (the same technique we used for the prisms, right?):
![Example 3](VolumeExample3.gif)
We summarized this investigation with the following theorem and examples of using it:
![Theorem 113 - Volume of Prism & Cylinder](Theorem113.gif)
Finally, we used this new theorem to solve the following example. When you're doing these problems, you should do it the way shown. Remember that the B stands for the "area of the base" and the H stands for the "height of the solid."
![Example 4](VolumeExample4.gif)
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